4^x*5^(2-x)=7^(3-2x)

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Solution for 4^x*5^(2-x)=7^(3-2x) equation: 



4^x*5^(2-x)=7^(3-2x)

We move all terms to the left:

4^x*5^(2-x)-(7^(3-2x))=0

We add all the numbers together, and all the variables

4^x*5^(-1x+2)-(7^(-2x+3))=0

Wy multiply elements

20x^2(--(7^(-2x+3))=0

We use the square of the difference formula

20x^2(+(7^(-2x+3))=0

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